【题中(X-Z)少了平方,否则当X=3/2、Y=3/4、Z=3/8时满足题意,但ABCD都不成立】
令 X-Y = a ,Y-Z = b ,
则 X-Z = (X-Y)+(Y-Z) = a+b ;
已知,(X-Z)²-4(X-Y)(Y-Z) = 0 ,
即有:(a+b)²-4ab = 0 ,
则有:(a-b)² = (a+b)²-4ab = 0 ,
可得:a-b = 0 ,
即有:(X-Y)-(Y-Z) = 0 ,
所以,Z+X-2Y = 0 ,
选 D .
【题中(X-Z)少了平方,否则当X=3/2、Y=3/4、Z=3/8时满足题意,但ABCD都不成立】
令 X-Y = a ,Y-Z = b ,
则 X-Z = (X-Y)+(Y-Z) = a+b ;
已知,(X-Z)²-4(X-Y)(Y-Z) = 0 ,
即有:(a+b)²-4ab = 0 ,
则有:(a-b)² = (a+b)²-4ab = 0 ,
可得:a-b = 0 ,
即有:(X-Y)-(Y-Z) = 0 ,
所以,Z+X-2Y = 0 ,
选 D .