Question

怎么求导数过一点的切线 不是在这点

Answer 1

用求导公式做

根据点的坐标 代入算

(v^n)'=nv^(n-1)

(ln v)'=v'/v

(e^v)'=e^v*v'

(sin v)'=cos v*v'

(cos v)'=-sin v*v'

(tan v)'=(sec v)^2*v'

(cot v)'=-(csc v)^2*v'

(sec v)'=sec v*tan v*v'

(csc v)'=-csc v*cot v*v'

(arcsin v)'=v'/(1-v^2)^(1/2)

(arccos v)'=-v'/(1-v^2)^(1/2)

(arctan v)'=v'/(1+v^2)

(arccot v)'=-v'/(1+v^2)

(arcsec v)'=v'/(v*(v^2-1)^(1/2))

(arccsc v)'=-v'/(v*(v^2-1)^(1/2))