初一求解一元一次方程:x+1/3-1=4-x/2

2个回答

  • (x+1)/3 - 1=(4-x)/2

    移项,得:(x+1)/3 - 1 - (4-x)/2=0

    通分,得:2(x+1)/6 - 6/6 - 3(4-x)/6=0

    展开,得:(2x+2-6-12+3x)/6=0

    合并同类项,得:(5x-16)/6=0

    解得:x=16/5

    (2y-1)/3=(y+2)/4 - 1

    移项,得:(2y-1)/3 - (y+2)/4 + 1=0

    通分,得:4(2y-1)/12 - 3(y+2)/12 + 12/12=0

    展开,得:(8y-4-3y-6+12)/12=0

    合并同类项,得:(5y+2)/12=0

    解得:y=-2/5

    4(y-1) - y=2(y + 1/2)

    展开:4y - 4 - y=2y + 1

    移项,得:4y - y - 2y=1 + 4

    合并同类项,得:y=5