Question

(2x^3y^3-2x^3y+1/8^4+y)/(-1/2x^3y)

Answer 1

(2x^3y^3-2x^3y+1/8^4+y)/(-1/2x^3y)

=-2(2x^3y^3-2x^3y+1/8^4+y)/(x^3y)

=-2(2y^2-2)+2(1/8^4+y)/(x^3y)

=-4y^2-4+2/8^4(x^3y)+2y/(x^3y)

=-4y^2-4+2/2^12(x^3y)+2/x^3

=-4y^2-4+1/2^11x^3y+2/x^3