设丢番图的寿命为x,剧描述可得如下关系式:
(1/6)x+(1/12)x+(1/7)x+5+(1/2)x+4=x
x=84
(1) 丢番图的寿命是84岁
(2) 丢番图开始当爸爸的年龄=(1/6)*84+(1/12)*84+(1/7)*84+5
=40岁
(3) 儿子死后丢番图的年龄=84-4=80岁
设丢番图的寿命为x,剧描述可得如下关系式:
(1/6)x+(1/12)x+(1/7)x+5+(1/2)x+4=x
x=84
(1) 丢番图的寿命是84岁
(2) 丢番图开始当爸爸的年龄=(1/6)*84+(1/12)*84+(1/7)*84+5
=40岁
(3) 儿子死后丢番图的年龄=84-4=80岁