Question

已知(m-2)x^m^2-3y+(n-5)xy^2+3关于xy的二次二项式试求3m^2-4mn+n^2的值

Answer 1

应为(m-2)x^m^2-3y+(n-5)xy^2+3关于xy的一次二项式

m-2=0,n-5=0

m=2,n=5

3m^2-4mn+n^2

=(3m-n)(m-n)

=(3*2-5)(2-5)

=1*(-3)

=-3