易知cI2=cH2=0.004mol/L
cHl=(0.1/10-0.004)*2=0.012mol/L
K=(Hl)^2/(H2)*(l2)=0.012^2/0.004^2=9
2.设生成Hl为2Xmol/L,反应达到平衡时H2,l2为(0.3-X)mol/L
(2X)^2/(0.3/10-X)^2=9
X=0.1,2X=0.2,0.3-X=0.2
Hl=0.2/(0.2*3)=0.33
易知cI2=cH2=0.004mol/L
cHl=(0.1/10-0.004)*2=0.012mol/L
K=(Hl)^2/(H2)*(l2)=0.012^2/0.004^2=9
2.设生成Hl为2Xmol/L,反应达到平衡时H2,l2为(0.3-X)mol/L
(2X)^2/(0.3/10-X)^2=9
X=0.1,2X=0.2,0.3-X=0.2
Hl=0.2/(0.2*3)=0.33