81^1/2-(1/8)^-1+3^0=?
1个回答
原式=9-8+1
=2
相关问题
(0.0081)^-1/4-[3*(7/8)^0]-1*[81^-0.25+(3*3/8)^-1/3]^-1/2
6.81-1.2-3.8=( ) 2.3+0.77+1.23+10.7
计算(1)0-(-2.8)-(+3.6)+(-1.5)+3.6-2.8(2)-15-[-1-(4-20)](3)(-81
0.81+15.3= 1300-497= 3-1/2= 3/4+0.72= 1÷0.04= 1/8÷0.625= 4.5
1,3,2,9,4,(),8.81
x:3=7/8:1/49:x=4.5/0.81/6:2/5=1/2:2x3/8:x=5%:0.6
7.8*2.4*81/2/3/5/1 3/10/1/2
计算2/3(1+1/3)(1+1/9)(1+1/81)(1+1/81²)
按规律填数:1,1,3,2,9,(),(),8,81
找规律填数(1)1,1.1,1.3,1.6,(),()3.1(2)0.81,0.64,0.49,0.36,(),()(3