(1)上述解题过程,从第③步开始出现错误;
(2)正确的写法为:c 2(a 2-b 2)=(a 2+b 2)(a 2-b 2),
移项得:c 2(a 2-b 2)-(a 2+b 2)(a 2-b 2)=0,
因式分解得:(a 2-b 2)[c 2-(a 2+b 2)]=0,
则当a 2-b 2=0时,a=b;当a 2-b 2≠0时,a 2+b 2=c 2;
(3)△ABC是直角三角形或等腰三角形或等腰直角三角形.
故答案为:(1)③;(2)当a 2-b 2=0时,a=b;当a 2-b 2≠0时,a 2+b 2=c 2;(3)△ABC是直角三角形或等腰三角形或等腰直角三角形.