阅读下列解题过程:已知a,b,c为△ABC的三边,且满足a 2 c 2 -b 2 c 2 =a 4 -b 4 ,试判断△

1个回答

  • (1)上述解题过程,从第③步开始出现错误;

    (2)正确的写法为:c 2(a 2-b 2)=(a 2+b 2)(a 2-b 2),

    移项得:c 2(a 2-b 2)-(a 2+b 2)(a 2-b 2)=0,

    因式分解得:(a 2-b 2)[c 2-(a 2+b 2)]=0,

    则当a 2-b 2=0时,a=b;当a 2-b 2≠0时,a 2+b 2=c 2

    (3)△ABC是直角三角形或等腰三角形或等腰直角三角形.

    故答案为:(1)③;(2)当a 2-b 2=0时,a=b;当a 2-b 2≠0时,a 2+b 2=c 2;(3)△ABC是直角三角形或等腰三角形或等腰直角三角形.