Question

sinx-√3cosx=0求x,范围是0如何从(1/2)sinx-(√3/2)cosx=0得到sinπ/6sinx-co

Answer 1

提取(√3)^2+1=4,开根号,等于2

就是提取2

2(1/2*sinx-√3/2*cosx=0)=0

1/2*sinx-√3/2*cosx=0)=0

cos(π/3)*sinx-sin(π/3)*cosx=0)=0

sin(x-π/3)=0

又0