x²+y²-xy+x -y/2 +1/4=04x²+4y²-4xy+4x-2y+1=04x²-4xy+y²+2(2x-y) +1+3y²=0(2x-y)²+2(2x-y)+1 +3y²=0(2x-y+1)²+3y²=0平方项恒非负,两平方项之和=0,两平方项...
已知实数x,y满足x2+y2-xy+x-1/2y+1/4=0 试求x,y的值
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