Question

a的平方（x-2）-3a=x+1 求x的值 ax+b-(3x+2ab)/3=0.5 求x的值

Answer 1

a^2（x-2）-3a=x+1

a^2x-x=2a^2+3a+1

(a^2-1)x=(2a+1)(a+1)

x=(2a+1)(a+1)/(a+1)(a-1)

x=(2a+1)/(a-1)

ax+b-(3x+2ab)/3=0.5

ax-x=0.5-b+2/3ab

x=(0.5-b+2/3ab)/(a-1)