Question

配制0.5mol/LNaOH溶液50ml需NaOH( )g,配制 0.1mol/LCuSO4溶液500mL,需胆矾（Cu

Answer 1

①配制0.5mol/L NaOH溶液50mL

m(NaOH)=cV*M=0.5*50*10^-3*40=1(g)

②配制0.1mol/L CuSO4溶液500mL

n(CuSO4·5H2O)=n(CuSO4)=cV=0.1*500*10^-3=0.05(mol)

m(CuSO4·5H2O)=n(CuSO4·5H2O)*M=0.05*250=12.5(g)

③配制0.2mol/L H2SO4溶液500mL

m(H2SO4)=cV*M=0.2*500*10^-3*98=9.8(g)

设需98%的浓H2SO4 V mL

ρV*98%=m(H2SO4)

V=m(H2SO4)/(ρ*98%)=9.8/(1.84*98%)=5.4(mL)