Question

什么求导得(sinωt)^2

Answer 1

因为 (sin ωt)^2 = (1 -cos 2ωt) /2,

所以 积分 (sin ωt)^2 dt = (1/2)积分 (1 -cos 2ωt) dt

= t /2 -(sin 2ωt) /2ω +C,

(C为任意常数).

即 F(t) = t /2 -(sin 2ωt) /2ω +C (C为任意常数) 求导得 (sinωt)^2 .