因为 A* (A*)* = |A*|E = |A|^(n-1) E
所以 AA* (A*)* = |A*|E = |A|^(n-1) A
所以 |A| (A*)* = |A*|E = |A|^(n-1) A
所以 (A*)* = |A|^(n-2) A
因为 A* (A*)* = |A*|E = |A|^(n-1) E
所以 AA* (A*)* = |A*|E = |A|^(n-1) A
所以 |A| (A*)* = |A*|E = |A|^(n-1) A
所以 (A*)* = |A|^(n-2) A