Question

若x=(1-a)/(1+a),y=(2-3a)/(3-2a)则用含x的代数式表示y为?

Answer 1

x=(1-a)/(1+a)

x+xa=1-a

a=(1-x)/(1+x)

y=(2-3a)/(3-2a)

3y-2ay=2-3a

a=(2-3y)/(3-2y)

(1-x)/(1+x)=(2-3y)/(3-2y)

(1-x)(3-2y)=(2-3y)(1+x)

3-3x-2y+2xy=2-3y+2x-3xy

1+5xy=-y+5x

5xy+y=5x-1

y=(5x-1)/(5x+1)