几个英文看的不是很清楚,根据当前的一些线索,题目中是求碳酸钙质量分数,样品3.10g;锥形瓶下面是个天平,无疑是检测系统的总质量,结合下图可以发现质量从开始起,逐步下降,说明反应一直在进行,直到后边趋向于稳定,可以认为此时反应进行彻底,结束了;锥形瓶中的溶液 acid 应该是某种酸.所以进行的反应肯定是CaCO3 +H离子→CO2 在 高中化学应该有提到一个质量差的问题,即△m,该反应的△m为44,只有CO2跑掉了,所以对应上图中减少的质量187.5-186.5=1g(这个看图我看那个线不是很清楚)根据这个就可以算出 反应的CaCO3有多少了,然后除以3.10g就能算出样品中的质量分数了
英语翻译An experiment was carried out to determine the percentag
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