Question

已知x的平方-4x+3=(x-1)的平方+m(x-1)+n,求m和n的值

Answer 1

x^2-4x+3=(x-1)^2+m(x-1)+n

=x^2-2x+1+mx-m+n

=x^2-(2-m)x+1-m+n

所以2-m=4

m=-2

1-m+n=3

1+2+n=3

n=0