16/25*(x^2-2x-1)^2+8/5*(x^2-2x-1)+1
2个回答
设t=x^2-2x-1
原式=(4/5t)^2-2*4/5t+1
=(4/5t-1)^2
=(4/5x^2-8/5x-9/5)^2
=(4x^2-8x-9)^2*(1/5)
相关问题
(x+1/x)(x2+1/x2)(x4+1/x4)(x8+1/x8)(x16+1/x16)(x2-1)
〔x+1/x)(x^2+1/x^2)(x^4+1/x^4)(x^8+1/x^8)(x^16+x^16)(x^2-1) 的
(x-1/2)(2x+1)(2x^2+1/2)(4x^4+1/4)(16x^8+1/16)÷(256x^16+1/256
解方程:(1)16(2x-1)2=25(x-2)2;(2)(x+2)2-10(x+2)+25=0.
解比例 2/8=9/x 1/2:1/5=1/4:x 1.25/0.25=x/1.6 40:x=2.5:15 1/2:x=
解方程 (1)3/5x=9/25 (2)11/8-2x=16/5
f(x)=1/1+x+2/1+x^2+4/1+x^4+8/1+x^8+16/1+x^16,求f(2)
3^2-1^2=8=8x1 5^2-3^2=16=8x2论证
3/5X-1/5X=24 X+2/3X=25 3/8X除以2=9/16
(1).(9y^2)-8x^2 (2).1-25x^2 (3).25/9m^2-16n^2 (4).(x+y)^2-(y