Question

用代入消元法解方程组 3(y-2）=x-17,2(x-1)=5y-8

Answer 1

3(y-2）=x-17,

3y-6=x-17

所以x=3y+11

代入2(x-1)=5y-8

2(3y+11-1)=5y-8

6y+20=5y-8

y=-28

x=3y+11=-73