初二数学题(整式的乘法)急用!①若(2x+y-1)的二次方+|x-2y-3|=0,求代数式(2x+y)(2x-y)-(x

3个回答

  • 1.(2x+y-1)^2+|x-2y-3|=0

    2x+y-1=0,x-2y-3=0

    x=1,y=-1

    (2x+y)(2x-y)-(x+2y)(x-2y-1)

    =4x^2-y^2-(x+2y)(x-2y)+(x+2y)

    =4x^2-y^2-x^2+4y^2+x+2y

    =3x^2-3y^2+x+2y

    =3-3+1+2*(-1)

    =-1

    2.(2x+3)(3x+2)-6x(x+3)+5x+6

    =6x^2+4x+9x+6-6x^2-18x+5x+6

    =12

    代数式(2x+3)(3x+2)-6x(x+3)+5x+6的值与x的取值无关.

    3.(x^2+px+8)*(x^2-3x-q)

    =x^4-3x^3-qx^2+px^3-3px^2-pqx+8x^2-24x-8q

    =x^4+(-3+p)x^3+(-q-3p+8)x^2+(-pq-24)x-8q

    积中不含 x的三次方 与x项

    -3+p=0,-pq-24=0

    p=3,q=-8

    4.:(x-y)[(x+y)(x+y)-xy]+(x+y)[(x-y)(x-y)+xy]

    =(x-y)[x^2+2xy+y^2-xy]+(x+y)[x^2-2xy+y^2+xy]

    =(x-y)(x^2+xy+y^2)+(x+y)(x^2-xy+y^2)

    =x^3-y^3+x^3+y^3

    =2x^3

    :(x-y)[(x+y)(x+y)-xy]+(x+y)[(x-y)(x-y)+xy]的值是2x^3, 它的值与 y无关

    5.a*b=ab+a-b

    a*b+(b-a)*b=ab+a-b+(b-a)b+(b-a)-b

    =ab+a-b+b^2-ab+b-a-b

    =b^2-