(1) 1-
1
10 0 2 =
99
100 ×
101
100 , 1-
1
200 5 2 =
2004
2005 ×
2006
2005 .
(2) (1-
1
2 2 )×(1-
1
3 2 ) …× (1-
1
200 4 2 )×(1-
1
200 5 2 )
=
1
2 ×
3
2 ×
2
3 ×
4
3 ×
2003
2004 ×
2005
2004 ×
2004
2005 ×
2006
2005
=
1
2 ×
2006
2005 .
=
1003
2005 .
故答案为:
99
100 ,
101
100 ;
2004
2005 ,
2006
2005 .