Question

一个铝球质量为27g,体积为20cm（三次方）,已知铝的密度p铝＝2.7×10（三次方）kg/m（三次方）,通过计算问这

Answer 1

p铝 = 2.7×10³ kg/m³ = 2.7 g/m³

V铝 = m/p铝 = 27/2.7 = 10 cm³ ＜V = 20 cm³ ,空心