Question

logx为底的2乘以 log2x为底的4=log8x为底的2

Answer 1

log2^2/log2^x*log2^4/log2^(2x)=log2^2/log2^(8x)

2(3+log2^x)=log2^x*（1+log2^x)

6+2log2^x=log2^x+(log2^x)^2

(log2^X)^2-log2^x-6=0

[(log2^x)+2][(log2^x)-3]=0

log2^x+2=0,log2^x-3=0

log2^x=-2,log2^x=3

x=2^(-2)=1/4,x=2^3=8