Question

∫1/(x^2+x)dx详细解答

Answer 1

∫ 1/(x² + x) dx

= ∫ [(x + 1) - x]/[x(x + 1)] dx

= ∫ [1/x - 1/(x + 1)] dx

= ln|x| - ln|x + 1| + c

= ln|x/(x + 1)| + c