1.△BHD∽△BCE
BH*BE=BD*BC
∠ABC=45°故△ABD为等腰Rt△,BD=AD
BE*AC=2S△ABC
=AD*BC=BD*BC=BH*BE
故BH=AC
2.AB=AC,BD=CE,∠ABD=45°=∠ACE
△ABD≌△ACE,AD=AE,△ADE是等腰三角形.
1.△BHD∽△BCE
BH*BE=BD*BC
∠ABC=45°故△ABD为等腰Rt△,BD=AD
BE*AC=2S△ABC
=AD*BC=BD*BC=BH*BE
故BH=AC
2.AB=AC,BD=CE,∠ABD=45°=∠ACE
△ABD≌△ACE,AD=AE,△ADE是等腰三角形.