已知,AB = 16 ,AB∶BC = 8∶3 ,则有:BC = 6 .
若点C在线段AB上,可得:DE = AD-AE = (1/2)(AB-AC) = (1/2)BC = 3 ;
若点C在线段AB的延长线上,可得:DE = AE-AD = (1/2)(AC-AB) = (1/2)BC = 3 ;
所以,DE的长为 3 .
已知,AB = 16 ,AB∶BC = 8∶3 ,则有:BC = 6 .
若点C在线段AB上,可得:DE = AD-AE = (1/2)(AB-AC) = (1/2)BC = 3 ;
若点C在线段AB的延长线上,可得:DE = AE-AD = (1/2)(AC-AB) = (1/2)BC = 3 ;
所以,DE的长为 3 .