3题三角函数问题,能答几题算几题~感激不尽

2个回答

  • 1、y=3sin(2x-π/3)最大值为3,此时2x-π/3=2kπ+π/2 即x=kπ+5π/12 (k∈R)

    2、cos(π+α)=-cosα=-3/5 cosα=3/5

    cos(5π/2-α)=cos(π/2-α)=sinα=±4/5

    tan(π+α)=tanα=±4/3

    3、sinθ+cosθ=2sinα ∴1+2sinθcosθ=4sin²α

    ∴2sinθcosθ=4sin²α-1=2(2sin²α-1)+1=1-2cos2α

    ∵sinθcosθ=sin^2β ∴2sinθcosθ=2sin^2β=1-(1-2sin^2β)=1-cos2β

    ∴1-2cos2α =1-cos2β ∴2cos2α =cos2β ∴4cos²2α =cos²2β