1/(ab+a+1)+1/(bc+b+1)+1/(ac+c+1)
=1/(ab+b+1)+a/(abc+ab+a)+ab/(a²bc+abc+ab)
=1/(ab+b+1)+a/(1+ab+a)+1b./(a+1+ab)
=(1+a+ab)/(ab+b+1)
=1
1/(ab+a+1)+1/(bc+b+1)+1/(ac+c+1)
=1/(ab+b+1)+a/(abc+ab+a)+ab/(a²bc+abc+ab)
=1/(ab+b+1)+a/(1+ab+a)+1b./(a+1+ab)
=(1+a+ab)/(ab+b+1)
=1