因为 f(x)=1+cos2x-2si n 2 (x-
π
6 ) =cos2x+cos(2x-
π
3 )=
3
2 cos2x+
3
2 sin2x =
3 sin(2x+
π
3 ),
则f(x)的图象向左平移m(m>0)个单位后使得图象的解析式为f(x)=
3 sin(2x+2m+
π
3 ),由题意
得2m+
π
3 =kπ+
π
2 ,k∈Z,∴m 最小值=
π
12 .
故选B.
因为 f(x)=1+cos2x-2si n 2 (x-
π
6 ) =cos2x+cos(2x-
π
3 )=
3
2 cos2x+
3
2 sin2x =
3 sin(2x+
π
3 ),
则f(x)的图象向左平移m(m>0)个单位后使得图象的解析式为f(x)=
3 sin(2x+2m+
π
3 ),由题意
得2m+
π
3 =kπ+
π
2 ,k∈Z,∴m 最小值=
π
12 .
故选B.