²-4ac=(2m-1)²-4m²
=-4m+1≥0
m≤1/4
∵x1²-x2²=(x1-x2)(x1+x2)=0
①当x1+x2=0时,
x1+x2=1-2m=0 m=1/2
②当x1-x2=0时,
x1=x2 b²-4ac=0
∴-4m+1=0 m=1/4
综上所得:当m=1/4时,满足题意.
²-4ac=(2m-1)²-4m²
=-4m+1≥0
m≤1/4
∵x1²-x2²=(x1-x2)(x1+x2)=0
①当x1+x2=0时,
x1+x2=1-2m=0 m=1/2
②当x1-x2=0时,
x1=x2 b²-4ac=0
∴-4m+1=0 m=1/4
综上所得:当m=1/4时,满足题意.