求lim x趋向0 (1-cosx^2)/[(x^2)*sinx^2]
2个回答
1-cos(x^2)~1/2·(x^2)^2=1/2·x^4
sinx^2~x^2
原式=lim[1/2·x^4/(x^2·x^2)]=1/2
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