x2分之x1平方+x1分之x2平方=x1x2分之x1三次方+x2三次方的和=(x1^3+x2^3)/(x1*x2)=(x1+x2)*(x1^2-x1*x2+x2^2)/(x1*x2)=(x1+x2)*[(x1+x2)^-3*x1*x2]/(x1*x2)=3/2*(9/4+6)/(-2)=-3/2*58/6*2=-29
x2分之x1平方+x1分之x2平方=x1x2分之x1三次方+x2三次方的和=(x1^3+x2^3)/(x1*x2)=(x1+x2)*(x1^2-x1*x2+x2^2)/(x1*x2)=(x1+x2)*[(x1+x2)^-3*x1*x2]/(x1*x2)=3/2*(9/4+6)/(-2)=-3/2*58/6*2=-29