∵ ∠EAD=48°∠D=90°∴ ∠AED=42°
∵ AE为平分线∠B=∠BAC∴∠BAE=∠CAE=½∠B
又 ∠AED为△ABE外角∴ ∠BAE+∠B=3∠BAE=∠AED=42°
推出 ∠B=28°∠BAE=∠CAE=14°
∵∠ACD为△ABC外角所以∠ACD=∠B+∠BAC=2∠B=56°
∵ ∠EAD=48°∠D=90°∴ ∠AED=42°
∵ AE为平分线∠B=∠BAC∴∠BAE=∠CAE=½∠B
又 ∠AED为△ABE外角∴ ∠BAE+∠B=3∠BAE=∠AED=42°
推出 ∠B=28°∠BAE=∠CAE=14°
∵∠ACD为△ABC外角所以∠ACD=∠B+∠BAC=2∠B=56°