Question

已知（x-1)³分之x²+2=（x-1)分之A+（x-1)²分之B+(x-1)³

Answer 1

（x-1)³分之x²+2

=（x-1)分之A+（x-1)²分之B+(x-1)³分之C,求A、B、C的值

=(A(x-1)²+B(x-1)+C)/(x-1)³;

∴Ax²+(B-2A)x+A-B+C=x²+2;

A=1;

B-2A=0;

B=2;

A-B+C=2;

C=2+2-1=3;

如果本题有什么不明白可以追问,