令2+x=t x=t-2
f(t)+f(2-t+2)=0
f(t)=-f(4-t)=f(t-4)
所以f(2012)=f(4*503)=f(4)=f(0)
f(2013)=f(4*503+1)=f(1)
f(2014)=f(4*503+2)=f(2)
x=0 f(2)+f(2)=0 f(2)=0
x=2 f(4)+f(0)=0 f(0)=0
所以f(2012)+f(2013)+f(2014)=9
令2+x=t x=t-2
f(t)+f(2-t+2)=0
f(t)=-f(4-t)=f(t-4)
所以f(2012)=f(4*503)=f(4)=f(0)
f(2013)=f(4*503+1)=f(1)
f(2014)=f(4*503+2)=f(2)
x=0 f(2)+f(2)=0 f(2)=0
x=2 f(4)+f(0)=0 f(0)=0
所以f(2012)+f(2013)+f(2014)=9