Question

请问一道因式分解的题目（初一）10AB-3+6B-5A-2B的3次+B方

Answer 1

10AB-3+6B-5A-2B^3+B^2

=(10AB-5A)+(B^2-3)+(6B-2B^3)

=(10AB-5A)+(B^2-3)-(2B^3-6B)

=5A(2B-1)+(B^2-3)-2B(B^2-3)

=5A(2B-1)+(B^2-3)(1-2B)

=5A(2B-1)-(B^2-3)(2B-1)

=(2B-1)[5A-(B^2-3)]

=(2B-1)(5A-B^2+3)