[3n+(-2)n]/[3(n+1)+(-2)(n+1)
=n/(n+1)
=(n+1-1)/(n+1)
=1-[1/(n+1)]
当n→0时,极限是1-1=0
当n→+∞时,极限是1
3n+(-2)n]/[3(n+1)+(-2)(n+1)的极限是多少?急
2个回答
相关问题
-
(-2)^n+3^n+1/3^n+2^n+1当n趋于无穷大时,函数的极限是多少
-
求极限lim [ 2^(n+1)+3^(n+1)]/2^n+3^n (n→∞)
-
[(2n+3n)/( 2n+1+3n+1)]的极限,n趋于无穷
-
lim(1+3+.+3^n)/(3^n+2^n)是多少 n趋向正无穷的极限
-
求极限 lim【1/（n^2+n+1）+2/（n^2+n+2）+3/（n^2+n+3）+……+n/（n^2+n+n）】n
-
证明(n2+n-1)/(3n2-2n)的极限为1/3
-
求极限Xn=1/(n^2+1)+2/(n^2+2)+3/(n^2+3)+……+n/(n^2+n)
-
求极限 1/(n^2+1^2)+2/(n^2+2^2)+3/(n^3+3^2)+...+n/(n^2+n^2)
-
求下列极限：（1）lim 3n^2-2n+1/8-n^3 n→∞ (2)lim 1+2+3+…+n/n^2 n→∞
-
求极限：lim(1/n+2^2/n^2+3^2/n^3+...+n^2/n^n) n→∞