Question

1.如图1,AOB是一条直线,OC是一条射线,∠AOC=2∠AOF,∠BOC=2∠BOE.

Answer 1

∠AOC+BOC=180

所以∠AOF+∠BOE=90

所以∠1+∠2=180-(∠AOF+∠BOE)=90

所以∠1和∠2互余

∠AOF和∠BOF互补

∠AOC和∠BOC互补

∠AOE和∠BOE互补

∠AOF和∠COE互余

∠AOF和∠BOE互余

∠COF和∠COE互余

∠COF和∠BOE互余