Question

将9.36gNacl与20g质量分数为98%,密度为1.84g/cm³的硫酸混合,微热使反应完全,再将所得气体全部通入4

Answer 1

c=1000*1.84*98%/98=18.4mol/L

n(H2SO4)=0.02*18.4=0.368mol

n(NaCl)=9.36/58.5=0.16mol（不足量）

n(HCl)=0.16mol

m(HCl)=0.16*58.5=5.84g

HCl%=5.84/(5.84+44.16)=0.1168