∫xe^(-x) dx=?从1积到0

2个回答

  • ∫xe^(-x) dx

    =-xe^(-x) -∫(-x)'e^(-x) dx

    =-xe^(-x)+∫e^(-x) dx

    =-xe^(-x)-e^(-x)

    =-(x+1)e^(-x)

    从1积到0

    [-(0+1)e^0]-[-(1+1)e^(-1)]

    =-1+2/e

    =(2/e)-1

    从2积分到正无穷

    [-(正无穷+1)*e^-无穷]-[-(2+1)e^(-2)]

    =0+3/e²

    =3/e²