混合气体的总的物质的量
6.72L
22.4L/mol =0.3mol,
令H 2和CO的物质的量分别为xmol、ymol,根据二者质量之和与体积之和列方程,则:
x+y=0.3
2x+28y=3.2
解得,x=0.2,y=0.1
m(H 2)=0.2mol×2g/mol=0.4g,
m(CO)=0.1mol×28g/mol=2.8g,
V(H 2)=0.2mol×22.4L/mol=4.48L,
V(CO)=0.1mol×22.4L/mol=2.24L,
故答案为:m(H 2)=0.4g,m(CO)=2.8g;V(H 2)=4.48L,V(CO)=2.24L.