设Y=lnx+sin x分之1.求dy
2个回答
y'=1/x-cosx/sin^2x
dy=(1/x-cosx/sin^2x)dx
相关问题
y=x*sin(lnx) 求dy
y=(x/lnx)+sin e 求dy
设y=e∧1/x+sin2x,求dy
设y=arctan根号(x^2-1)-lnx/根号(x^2-1)求dy
设y=sin2x/(1+x^2),求dy/dx,
设函数y=sin²x+2x,求dy
设y等于e的x分之-1次方,求dx分之dy
设函数y=y(x)由方程x^y+y^2lnx+2=0确定,求dy
设y=f(x)是由方程xy+lnx+y=1所确定的函数,求dy.
设函数y=x^2sin(sinx),求dy/dx