tan(α+π/4)+tan(α-π/4)=2tan2α

1个回答

  • tan(α+π/4)+tan(α-π/4) ..用公式拆开

    =(tanα+tanπ/4)/(1-tanαtanπ/4)+(tanα-tanπ/4)/(1+tanαtanπ/4) ..将tanπ/4写成1

    =(1+tanα)/(1-tanα)+(tanα-1)/(1+tanα)

    =(1+tanα)/(1-tanα)-(1-tanα)/(tanα+1) ..通分

    =[(1+tanα)^2-(1-tanα)^2]/(1+tanα)(1-tanα) ..去括号

    =[1+2tanα+(tanα)^2-1+2tanα-(tanα)^2]/(1+tanα)(1-tanα) ..约简

    =4tanα/1^2-(tanα)^2

    =2*[2tanα/1^2-(tanα)^2] ..代公式

    =2tan2α