Question

secθ=x/5 0

Answer 1

sceθ=x/5,θ∈(0,π/2)

所以,cosθ=5/x∈(0,1)

则,x∈(5,+∞)

且,tanθ=√(x^2-25)/x

所以,ln|secθ+tanθ|=ln|(x/5)+√(x^2-25)/x|=|ln[x+√(x^2-25)]/x|

=ln{x+√(x^2-25)]/x}

=ln[x+√(x^2-25)]-lnx