2x²-3x+2=0,两边都除以2x,
x-3/2+1/x=0,即x+1/x=3/2
(x+1/x)³=x³+1/x³+3x+3/x,故x³+1/x³=(x+1/x)³-3(x+1/x)=(3/2)³-3×3/2=-9/8