[2x(x²y-xy²)+xy(2xy-x²)]÷x²y
=[2x×xy(x-y)+xy×x(2y-x)]÷x²y
={x²y[2(x-y)+(2y-x)]}÷x²y
=2(x-y)+(2y-x)
=2x-2y+2y-x
=x
取x=1时,代数式=1
化简[2x(x²y-xy²)+xy(2xy-x²)]÷x²y,并选择你喜欢的x,y的值代入求值.
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