x^2-4x-12=x^2+4x+4

1个回答

(6x+12)/(x^2+4x+4)+(4-x^2)/(x^2-4x+4)=(x^2)/(4-x^2)
9x-2.4x=75x+12*4=93 2x+4.2*4=27 12x+4x=78.4（x+2.8)*5=37.5 4x
求解分式方程.(6x+12)/(x^2+4x+4)-(x^2-4)/(x^2-4x+4)+x^2/(x^2-4)=0
x-12x-4=0 x-2x=2 x-4x-12=0 (x+1)-4=0 (3x+2)
因式分解(4x^2-12x)(4x^2-12x+18)+81
(x^2-4x)^2+7(x^2-4x)+12因式分解
(x^2-4x-12)(x^2-4x+3)+56
4×2.5-4X=2 10-4X=2 10-4X+10=2+10 4X=12 4X÷4=12÷4 X=3 错误在哪?
18+2(4x-3)=10x12.8-2.4x=4（x+2）
∫(x^4+2x^2+4x+1)/( x^2+1)^3}dx 和 ∫(2x^2-12x+4)/(x^3-4x^2)dx,