∵X²-X-2=0
∴x²-x=2
(X²-X)²-1+根号3分之X²-X+2根号3
=[(x²-x+2√3]/[(x²-x)²-1+√3]
=(2+2√3)/(4-1+√3)
=(2+2√3)(3-√3)/(3+√3)(3-√3)
=(6+6√3-2√3-6)/(9-3)
=4√3/6
=2√3/3
∵X²-X-2=0
∴x²-x=2
(X²-X)²-1+根号3分之X²-X+2根号3
=[(x²-x+2√3]/[(x²-x)²-1+√3]
=(2+2√3)/(4-1+√3)
=(2+2√3)(3-√3)/(3+√3)(3-√3)
=(6+6√3-2√3-6)/(9-3)
=4√3/6
=2√3/3