求解(x-1/2)(x的平方+1/4)(x+1/2)

1个回答

  • (x-1/2)(x^2+1/4)(x+1/2)

    =(x-1/2)(x+1/2)(x^2+1/4)

    =(x^2-1/4)(x^2+1/4)

    =x^4-1/16

    (x+y-z)(x+y+z)

    =[(x+y)-z][(x+y)+z]

    =(x+y)^2-z^2

    =x^2+2xy+y^2-z^2

    (a-b+c)(a+b-c)

    =[a-(b-c)][a+(b-c)]

    =a^2-(b-c)^2

    =a^2-b^2+2bc-c^2

    [2a^2-(a+b)(a-b)][(c-a)(c+a+(b-c)c+b)]

    =(2a^2-a^2+b^2)[(c-a)(c+a+bc-c^2+b)]

    =(a^2+b^2)[(c-a)(c+a+bc-c^2+b)]……你看下后面的括号对么,题目应该不会出这样的

    (a+b+c)^2-(a-b+c)^2

    =(a+b+c+a-b+c)(a+b+c-a+b-c)

    =(2a+2c)2b

    =4ab+4bc